Summary: Aerodynamics
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Read the summary and the most important questions on Aerodynamics
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1 Aerodynamics
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1.1 Fundamental Equations
This is a preview. There are 27 more flashcards available for chapter 1.1
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By which fundamental quantities can we characterize the flow?
- Pressure
- Velocity
- Temperature
- Density
And the derivatives of these quantities (changes in time) -
What are the three fundamental equations?
- Continuity equation
- Euler equation
- Bernouli equation
- Continuity equation
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What is pressure and how can we describe it?
The pressure is the norme force per unit area on a surface. -
How can a perfect gas be described?
A perfect gas is a gas in which intermolecular forces are negligible. -
How can the equation of state be approximated for an actual gas?
By theBerthelot equation. -
When does the difference between the Berthelot equation and the equation of state become te smallest?
The difference with the equation of state for a perfect gas becomes smaller as p decreases or T increases.
So when the distance between the molecules increases. -
Ex. 1Compute the temperature in a point on a wing of a Boeing 747, where pressure and density are given to be:0.7 x 10^5 N/m2 and 0.91 kg/m3(about 3000m standard atmosphere)
Perfect gass --> P = ρRT
P = 0.7 x 10^5 N/m2
ρ = 0.91 kg/m3
R = 287.0 J/kg K
T = P / ( ρR)
T= 0.7 x 10^5 / (0.91 * 287) = 268.0 K -
What are the pressure, denisity and temperature at sea level / standard conditions?
Ps = 1.01325*10^5 N/m2
ρs = 1.225 kg/m3
Ts = 288.15 K -
Ex. 2Compute the total mass of air in a room of30 m x 15 m x 5 m under standard atmosphericconditions at sea level.
ρ = m / V
m = V * ρ
V = 30 x 15 x 5 = 2250 m3
ρ = 1.225 kg/m3
m = 2756 kg -
Ex. 3Compute the density and specific volume of air in a wind tunnel at P = 1.0 bar, and -100 C.
Pv = RT because
P = RTρ with ρ = 1 / v
P = 1*10^5 kg / m2
T = -100 + 273.15 = 173.15 K
R = 287.0 J/ kg K
v = RT / P
v = 287.0 * 173.15 / 101325 = 0.50 m3/kg
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