General Chemistry - Equilibrium
3 important questions on General Chemistry - Equilibrium
Equilibrium constant in equation w/ multiple steps
Keq = kf1*kf2*kf3 / Kr1*kr2*kr3 = [overall products]^coefficient / [overall reactants]^coefficient
= law of mass action
= law of mass action
Change in pressure or volume
At constant temp., a change in pressure causes a change in volume and vice versa.
Has the most effect on gases as most compressible
↑ Pressure, ↓ moles of gas, ↓ volume - reaction favors side where fewer moles of gas are present
↑ Volume, ↓ Pressure, ↑ moles of gas - reaction favors side where more moles of gas are present
Has the most effect on gases as most compressible
↑ Pressure, ↓ moles of gas, ↓ volume - reaction favors side where fewer moles of gas are present
↑ Volume, ↓ Pressure, ↑ moles of gas - reaction favors side where more moles of gas are present
Solubility product constant
Each salt has its own disinct Ksp, which shows its solubility in aqueous solution
Ksp = [A]^m[B]^n
where A and B = ions in solution
m and n represent there stoichiometric coeffectients in solution
Given the solubility of a salt, we see that Xmoles of salt/liter of solution can dissociate.
Using that information we can determine how many moles of each ion will form based on the dissociation reaction
Using those values we write the Ksp equation and fill in the blanks
Ksp = [A]^m[B]^n
where A and B = ions in solution
m and n represent there stoichiometric coeffectients in solution
Given the solubility of a salt, we see that Xmoles of salt/liter of solution can dissociate.
Using that information we can determine how many moles of each ion will form based on the dissociation reaction
Using those values we write the Ksp equation and fill in the blanks
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